What is the inverse of f(x)=((x^5)/5-1)^{1/3} ?

The inverse of f(x)=((x^5)/5-1)^{1/3} is \sqrt[5]{5x^3+5}

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inverse of f(x)=((x^5)/5-1)^{1/3}

inverse

f (x) = (\frac{x ^{5}}{5} - 1)^{\frac{1}{3}}

Solution steps

y = (\frac{x ^{5}}{5} - 1)^{\frac{1}{3}}

Replace

x

with

y

x = (\frac{y ^{5}}{5} - 1)^{\frac{1}{3}}

Solve for

y, x = (\frac{y ^{5}}{5} - 1)^{\frac{1}{3}}

\frac{x - 8}{x + 7}

f (x) = \frac{1}{x ^{2} - 6 x + 12}

f (x) = ∣ 2 x + 3 ∣

f (x) = x^{5} - 20 x^{2}

f (x) = \frac{x + 5}{x ^{2} - 36}

What is the inverse of f(x)=((x^5)/5-1)^{1/3} ?
The inverse of f(x)=((x^5)/5-1)^{1/3} is \sqrt[5]{5x^3+5}