What is the asymptotes of f(x)=(x+1)/(x^2+x-6) ?

The asymptotes of f(x)=(x+1)/(x^2+x-6) is Vertical: x=-3,x=2,Horizontal: y=0

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asymptotes of f(x)=(x+1)/(x^2+x-6)

asymptotes

f (x) = \frac{x + 1}{x ^{2} + x - 6}

Vertical : x = - 3, x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 1}{x ^{2} + x - 6} : x = - 3, x = 2

Horizontal Asymptotes of

\frac{x + 1}{x ^{2} + x - 6} : y = 0

Slant Asymptotes of

\frac{x + 1}{x ^{2} + x - 6} :

None

Vertical : x = - 3, x = 2, Horizontal : y = 0

f (x) = lo g_{5} (x - 6) + 2

f (x) = 27 x^{3} + 1

f (x) = x - 1 + 2

3 - 4 sin (\frac{2}{3} (x - 1))

f (x) = (x + 5)^{2}

What is the asymptotes of f(x)=(x+1)/(x^2+x-6) ?
The asymptotes of f(x)=(x+1)/(x^2+x-6) is Vertical: x=-3,x=2,Horizontal: y=0