What is the critical f(x)= x/(x^2-9) ?

The critical f(x)= x/(x^2-9) is None

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critical f(x)= x/(x^2-9)

critical points

f (x) = \frac{x}{x ^{2} - 9}

None

Solution steps

\frac{x}{x ^{2} - 9}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} - 9} : x < - 3 or - 3 < x < 3 or x > 3

\frac{x}{x ^{2} - 9}

is not defined at

x = - 3, x = 3

, therefore:

None

f (x) = ln (\frac{( 5 - x )}{( 4 - x )})

y = ∣ x - 1 ∣ + 2

f (x) = - 4 x^{2} + 4 x + 1

f (x) = - 2 x + 3

f (x) = \frac{x ^{2} + 6 x - 7}{x ^{2} + 2 x - 3}