What is the line (-11/3 ,0),(0, 11/2) ?

The line (-11/3 ,0),(0, 11/2) is y= 3/2 x+11/2

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line (-11/3 ,0),(0, 11/2)

line

(- \frac{11}{3}, 0), (0, \frac{11}{2})

y = \frac{3}{2} x + \frac{11}{2}

Solution steps

Find the line

y = mx + b

passing through

(- \frac{11}{3}, 0)

(0, \frac{11}{2})

Compute the slope

(- \frac{11}{3}, 0), (0, \frac{11}{2}) : m = \frac{3}{2}

Compute the

y

intercept:

b = \frac{11}{2}

Construct the line equation

y = mx + b

where

m = \frac{3}{2}

and

b = \frac{11}{2}

y = \frac{3}{2} x + \frac{11}{2}

f (x) = 4 x^{2} - 16 x + 9

f (x) = \frac{∣ x - 5 ∣}{x - 5}

f (x) = 5 x

\frac{1}{x ^{2}} - 4

f (x) = - \frac{5}{4} x - 10

What is the line (-11/3 ,0),(0, 11/2) ?
The line (-11/3 ,0),(0, 11/2) is y= 3/2 x+11/2