What is the inverse of f(x)=((x-7))/(2x+1) ?

The inverse of f(x)=((x-7))/(2x+1) is (-7-x)/(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=((x-7))/(2x+1)

inverse

f (x) = \frac{( x - 7 )}{2 x + 1}

\frac{- 7 - x}{2 x - 1}

Solution steps

y = \frac{x - 7}{2 x + 1}

Replace

x

with

y

x = \frac{y - 7}{2 y + 1}

Solve for

y, x = \frac{y - 7}{2 y + 1}

\frac{- 7 - x}{2 x - 1}

e^{x - 3}

x + 3 - x

f (x) = \frac{2}{x + 4}

f (x) = x^{7} + 1

f (x) = \frac{1}{2} y^{2} - 1

What is the inverse of f(x)=((x-7))/(2x+1) ?
The inverse of f(x)=((x-7))/(2x+1) is (-7-x)/(2x-1)