What is the inverse of f(x)= 1/2 y^2-1 ?

The inverse of f(x)= 1/2 y^2-1 is sqrt(2y+2),-sqrt(2y+2)

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inverse of f(x)= 1/2 y^2-1

inverse

f (x) = \frac{1}{2} y^{2} - 1

2 y + 2, - 2 y + 2

Solution steps

x = \frac{1}{2} y^{2} - 1

Replace

y

with

x

y = \frac{1}{2} x^{2} - 1

Solve for

x, y = \frac{1}{2} x^{2} - 1

2 y + 2, - 2 y + 2

7 x^{2} - 2

16 - x^{2}

y = \frac{7}{8} x - 7

f (x) = 2 x - 3

f (x) = 4 - 6 x

What is the inverse of f(x)= 1/2 y^2-1 ?
The inverse of f(x)= 1/2 y^2-1 is sqrt(2y+2),-sqrt(2y+2)