What is the domain of f(x)= 1/(x^2+4x-32) ?

The domain of f(x)= 1/(x^2+4x-32) is x 4

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domain of f(x)= 1/(x^2+4x-32)

domain

f (x) = \frac{1}{x ^{2} + 4 x - 32}

x < - 8 or - 8 < x < 4 or x > 4

Interval Notation

(- \infty, - 8) \cup (- 8, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 8

The function domain

x < - 8 or - 8 < x < 4 or x > 4

f (x) = e^{7 x - 6}

(x - 5)^{3}

\frac{1}{x - 4}

f (x) = lo g_{5} (x - 1) + 4

x^{2} - 7 x - 30

What is the domain of f(x)= 1/(x^2+4x-32) ?
The domain of f(x)= 1/(x^2+4x-32) is x<-8\lor-8<x<4\lor x>4