What is the monotone f(x)=sqrt(x^2-1) ?

The monotone f(x)=sqrt(x^2-1) is Decreasing:-infinity <x<-1,Increasing:1<x<infinity

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monotone f(x)=sqrt(x^2-1)

monotone intervals

f (x) = x^{2} - 1

Decreasing : - \infty < x < - 1, Increasing : 1 < x < \infty

Solution steps

f^{'} (x) = \frac{x}{x ^{2} - 1}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: 1 < x < \infty

Decreasing : - \infty < x < - 1, Increasing : 1 < x < \infty

f (x) = \frac{2 x + 8}{x ^{2} - 3 x - 18}

f (x) = \frac{5}{2 4 + 5 x}

2 cos (3 x + \frac{π}{2})

f (x) = \frac{( x - 2 )}{( 1 - 3 x )}

y = x^{2} + 4

What is the monotone f(x)=sqrt(x^2-1) ?
The monotone f(x)=sqrt(x^2-1) is Decreasing:-infinity <x<-1,Increasing:1<x<infinity