What is the extreme f(x)=x^4-2x^2 ?

The extreme f(x)=x^4-2x^2 is Minimum(-1,-1),Maximum(0,0),Minimum(1,-1)

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extreme f(x)=x^4-2x^2

extreme points

f (x) = x^{4} - 2 x^{2}

Minimum (- 1, - 1), Maximum (0, 0), Minimum (1, - 1)

Solution steps

f^{'} (x) = 4 x^{3} - 4 x

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{4} - 2 x^{2} : - 1

Minimum (- 1, - 1)

Plug

x = 0

into

x^{4} - 2 x^{2} : 0

Maximum (0, 0)

Plug

x = 1

into

x^{4} - 2 x^{2} : - 1

Minimum (1, - 1)

Minimum (- 1, - 1), Maximum (0, 0), Minimum (1, - 1)

f (x) = ln (x + 3)

y = - x^{3} + 3

\frac{( x + 2 )}{( x + 6 )}

\frac{( 2 - x ^{2} )}{( x ^{2} - 9 )}

What is the extreme f(x)=x^4-2x^2 ?
The extreme f(x)=x^4-2x^2 is Minimum(-1,-1),Maximum(0,0),Minimum(1,-1)