What is the range of 6sin(1/6 x) ?

The range of 6sin(1/6 x) is -6<= f(x)<= 6

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range of 6sin(1/6 x)

range

6 sin (\frac{1}{6} x)

- 6 \leq f (x) \leq 6

Interval Notation

[- 6, 6]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (\frac{1}{6} x) \leq 1

- 1 \leq sin (\frac{1}{6} x) \leq 1

Multiply the edges of the range by:

6

- 6 \leq 6 sin (\frac{1}{6} x) \leq 6

Therefore the range is

- 6 \leq f (x) \leq 6

f (x) = - 10 cos (10 x + \frac{π}{3})

y = 3 x - 6

cos^{3} (x)

- \frac{8}{x ^{2}}

\frac{cos ( x )}{2 + sin ( x )}