What is the critical f(x)=9x^3-3x ?

The critical f(x)=9x^3-3x is x=-1/3 ,x= 1/3

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critical f(x)=9x^3-3x

critical points

f (x) = 9 x^{3} - 3 x

x = - \frac{1}{3}, x = \frac{1}{3}

Solution steps

9 x^{3} - 3 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{3}, x = \frac{1}{3}

Identify critical points not in

f (x)

domain

Domain of

9 x^{3} - 3 x : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{3}, x = \frac{1}{3}

1 - (\frac{1}{2}) + (\frac{1}{3}) - (\frac{1}{4}) + (\frac{1}{5})

\frac{tan ( 4 x )}{x}

4 x - 2 - 8

f (x) = 14 - x