What is the inverse of f(x)=(x-1)^2+2 ?

The inverse of f(x)=(x-1)^2+2 is sqrt(x-2)+1,-sqrt(x-2)+1

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inverse of f(x)=(x-1)^2+2

inverse

f (x) = (x - 1)^{2} + 2

x - 2 + 1, - x - 2 + 1

Solution steps

y = (x - 1)^{2} + 2

Replace

x

with

y

x = (y - 1)^{2} + 2

Solve for

y, x = (y - 1)^{2} + 2

x - 2 + 1, - x - 2 + 1

f (x) = \frac{x + 2}{x ^{2} - 1}

f (x) = 2 (\frac{1}{2})^{x}

(4, 2), (3, 5)

f (y) = - 4 x - 5

f (x) = x^{2} ln (\frac{x}{8})

What is the inverse of f(x)=(x-1)^2+2 ?
The inverse of f(x)=(x-1)^2+2 is sqrt(x-2)+1,-sqrt(x-2)+1