What is the domain of f(x)=sqrt(-2/3 (x-1/2))-3 ?

The domain of f(x)=sqrt(-2/3 (x-1/2))-3 is x<= 1/2

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domain of f(x)=sqrt(-2/3 (x-1/2))-3

domain

f (x) = - \frac{2}{3} (x - \frac{1}{2}) - 3

x \leq \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{1}{2}

The function domain

x \leq \frac{1}{2}

f (x) = lo g_{10} (x + 4)

f (x) = \frac{x + 7}{24 - x ^{2} - 49}

f (x) = \frac{7 - 3 x}{x - 2}

f (x) = x + 3 \cdot (\frac{8}{x})

f (x) = e^{2 x}

What is the domain of f(x)=sqrt(-2/3 (x-1/2))-3 ?
The domain of f(x)=sqrt(-2/3 (x-1/2))-3 is x<= 1/2