What is the extreme (1664-64y^2)y^2 ?

The extreme (1664-64y^2)y^2 is Maximum(-sqrt(13),10816),Minimum(0,0),Maximum(sqrt(13),10816)

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extreme (1664-64y^2)y^2

extreme points

(1664 - 64 y^{2}) y^{2}

Maximum (- 13, 10816), Minimum (0, 0), Maximum (13, 10816)

Solution steps

f^{'} (y) = - 256 y (y + 13) (y - 13)

Find intervals:

Increasing

: - \infty < y < - 13,

Decreasing

: - 13 < y < 0,

Increasing

: 0 < y < 13,

Decreasing

: 13 < y < \infty

Plug

y = - 13

into

(1664 - 64 y^{2}) y^{2} : 10816

Maximum (- 13, 10816)

Plug

y = 0

into

(1664 - 64 y^{2}) y^{2} : 0

Minimum (0, 0)

Plug

y = 13

into

(1664 - 64 y^{2}) y^{2} : 10816

Maximum (13, 10816)

Maximum (- 13, 10816), Minimum (0, 0), Maximum (13, 10816)

f (x) = \frac{x - 1}{x + 5}

x^{\frac{7}{2}} - 4 x^{2}

f (x) = \frac{8 + x ^{4}}{x ^{2} - x ^{4}}

(3, 2), (- 4, - 1)

\frac{x}{4 + x}

What is the extreme (1664-64y^2)y^2 ?
The extreme (1664-64y^2)y^2 is Maximum(-sqrt(13),10816),Minimum(0,0),Maximum(sqrt(13),10816)