What is the inverse of f(x)=((x-2))/((x+2)) ?

The inverse of f(x)=((x-2))/((x+2)) is (-2-2x)/(x-1)

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inverse of f(x)=((x-2))/((x+2))

inverse

f (x) = \frac{( x - 2 )}{( x + 2 )}

\frac{- 2 - 2 x}{x - 1}

Solution steps

y = \frac{x - 2}{x + 2}

Replace

x

with

y

x = \frac{y - 2}{y + 2}

Solve for

y, x = \frac{y - 2}{y + 2}

\frac{- 2 - 2 x}{x - 1}

f (x) = \frac{x - 4}{x ^{2} - 12 x + 32}

y = - \frac{5}{4} x - 2, (10, - 10)

csc (csc (x))

\frac{3}{- 1} + 2

- x^{3} - x^{2} + 16 x + 16

What is the inverse of f(x)=((x-2))/((x+2)) ?
The inverse of f(x)=((x-2))/((x+2)) is (-2-2x)/(x-1)