What is the domain of f(x)= 1/(sqrt(1-x^2)) ?

The domain of f(x)= 1/(sqrt(1-x^2)) is -1<x<1

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domain of f(x)= 1/(sqrt(1-x^2))

domain

f (x) = \frac{1}{1 - x ^{2}}

- 1 < x < 1

Interval Notation

(- 1, 1)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

- 1 < x < 1

- 3 sec (π - 2 x) + 5, 0 \leq x \leq 2 π

x + 1

\frac{1}{x + 2} - 3

f (x) = - 8 x^{3} + 6 x + 6

f (x) = \frac{x + 1}{x ^{2} - 2 x - 3}

What is the domain of f(x)= 1/(sqrt(1-x^2)) ?
The domain of f(x)= 1/(sqrt(1-x^2)) is -1<x<1