What is the domain of f(x)=sqrt(x^3-1) ?

The domain of f(x)=sqrt(x^3-1) is x>= 1

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domain of f(x)=sqrt(x^3-1)

domain

f (x) = x^{3} - 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = 5 x - 2

\frac{x + 2}{x - 1}

y = \frac{x + 8}{x ^{2} - 9}

f (x) = \frac{- 5 x + 1}{- 6 x + 4}

f (x) = \frac{8 - x}{3}

What is the domain of f(x)=sqrt(x^3-1) ?
The domain of f(x)=sqrt(x^3-1) is x>= 1