en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^2+2x-5

Solution

extreme points

f (x) = x^{2} + 2 x - 5

Solution

Minimum (- 1, - 6)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x - 5 : - 6

Minimum (- 1, - 6)

Popular Examples

critical f(x)=e^{-x}critical points

f (x) = e^{- x}

f (x) = ln (1 + x)

range of (5x+1)/(x-3)range

\frac{5 x + 1}{x - 3}

parallel 3y-8x=21 parallel

3 y - 8 x = 21

intercepts of 98x-49x^2-45 intercepts

98 x - 49 x^{2} - 45

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+2x-5 ?
The extreme f(x)=x^2+2x-5 is Minimum(-1,-6)