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Popular >

midpoint (1,-1),(4,-6)

Solution

midpoint

(1, - 1), (4, - 6)

Solution

(\frac{5}{2}, - \frac{7}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (1, - 1), (x_{2}, y_{2}) = (4, - 6)

= (\frac{4 + 1}{2}, \frac{- 6 - 1}{2})

Refine

= (\frac{5}{2}, - \frac{7}{2})

Popular Examples

f (x) = arccos (x)

slope of m=-1 slope

m = - 1

symmetry xy=12 symmetry

x y = 12

domain of f(x)=1-2^x domain

f (x) = 1 - 2^{x}

monotone f(x)=2x^3+15x^2+7 monotone intervals

f (x) = 2 x^{3} + 15 x^{2} + 7

Frequently Asked Questions (FAQ)

What is the midpoint (1,-1),(4,-6) ?
The midpoint (1,-1),(4,-6) is (5/2 ,-7/2)