What is the domain of \sqrt[4]{x^2-3x} ?

The domain of \sqrt[4]{x^2-3x} is x = 3

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domain of \sqrt[4]{x^2-3x}

domain

x \leq 0 or x \geq 3

Interval Notation

(- \infty, 0] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 3

The function domain

x \leq 0 or x \geq 3

f (x) = x^{4} - 1

x^{4} + 4 x^{3} - 48 x^{2} + 6

(0, - 6), (14, 0)

y = 2 x - 7

y = \frac{1}{4} x, (4, - 8)

What is the domain of \sqrt[4]{x^2-3x} ?
The domain of \sqrt[4]{x^2-3x} is x<= 0\lor x>= 3