What is the critical f(x)=4x^2(x-6) ?

The critical f(x)=4x^2(x-6) is x=0,x=4

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critical f(x)=4x^2(x-6)

critical points

f (x) = 4 x^{2} (x - 6)

x = 0, x = 4

Solution steps

4 x^{2} (x - 6)

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4

Identify critical points not in

f (x)

domain

Domain of

4 x^{2} (x - 6) : - \infty < x < \infty

All critical points are in domain

x = 0, x = 4

f (x) = x^{3} + 3 x^{2} - 4 x - 12

f (x) = \frac{5 t}{t ^{2} + 25}

f (x) = \frac{4}{x - 5}

y = - 4 x^{2}

f (x) = x^{2} - x + 1