What is the critical f(x)=(x^2)/2-4x+7 ?

The critical f(x)=(x^2)/2-4x+7 is x=4

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critical f(x)=(x^2)/2-4x+7

critical points

f (x) = \frac{x ^{2}}{2} - 4 x + 7

x = 4

Solution steps

\frac{x ^{2}}{2} - 4 x + 7

Find where

f^{'} (x)

is equal to zero or undefined

x = 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{2} - 4 x + 7 : - \infty < x < \infty

All critical points are in domain

x = 4

x^{2} + 4 x - 2

f (x) = \frac{12 x ^{4}}{( 3 x + 1 ) ^{4}}

f (x) = 3 sin^{2} (x)

f (x) = \frac{3 a ^{2} + 5 a}{2 a - 3}

\frac{2 x ^{2} + 2 x - 12}{x ^{2} + x}