What is the critical f(x)=x^2-ln(x) ?

The critical f(x)=x^2-ln(x) is x= 1/(sqrt(2))

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critical f(x)=x^2-ln(x)

critical points

f (x) = x^{2} - ln (x)

x = \frac{1}{2}

Solution steps

x^{2} - ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}, x = \frac{1}{2}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} - ln (x) : x > 0

x^{2} - ln (x)

is not defined at

x = - \frac{1}{2}, x = 0

, therefore:

x = \frac{1}{2}

x + 3 - \frac{7 - x}{x}

2 x - 1

y = 9 - x

f (x) = \frac{x ^{2}}{5} + 5

x + 5 y = 15

What is the critical f(x)=x^2-ln(x) ?
The critical f(x)=x^2-ln(x) is x= 1/(sqrt(2))