What is the domain of f(x)=sin((x+1)/(x-1)) ?

The domain of f(x)=sin((x+1)/(x-1)) is x 1

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domain of f(x)=sin((x+1)/(x-1))

domain

f (x) = sin (\frac{x + 1}{x - 1})

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

\frac{5 x ^{2} - 10 x + 1}{x - 2}

f (x) = \frac{2}{2 x - 5}

(- 2, - 2), (4, 8)

\frac{x ^{2} - 9}{x ^{2} + 3 x}

3 x^{2} + 5 x - 4

What is the domain of f(x)=sin((x+1)/(x-1)) ?
The domain of f(x)=sin((x+1)/(x-1)) is x<1\lor x>1