What is the domain of f(x)=sqrt((9-7x)/(6+9x)) ?

The domain of f(x)=sqrt((9-7x)/(6+9x)) is -2/3 <x<= 9/7

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domain of f(x)=sqrt((9-7x)/(6+9x))

domain

f (x) = \frac{9 - 7 x}{6 + 9 x}

- \frac{2}{3} < x \leq \frac{9}{7}

Interval Notation

Solution steps

Find non-negative values for radicals:

- \frac{2}{3} < x \leq \frac{9}{7}

Find undefined (singularity) points:

x = - \frac{2}{3}

Combine real regions and undefined points for final function domain

- \frac{2}{3} < x \leq \frac{9}{7}

4 x + 5 y = 6

f (x) = - 5 (x + 4)^{2} + 2

Y (x) = \frac{2 x - 9}{x - 3}

f (x) = 2 \cdot 3^{x}

sin (x) + cos (x)

What is the domain of f(x)=sqrt((9-7x)/(6+9x)) ?
The domain of f(x)=sqrt((9-7x)/(6+9x)) is -2/3 <x<= 9/7