What is the inverse of f(x)=(x-3)^2,x>= 3 ?

The inverse of f(x)=(x-3)^2,x>= 3 is sqrt(x)+3,-sqrt(x)+3

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inverse of f(x)=(x-3)^2,x>= 3

inverse

f (x) = (x - 3)^{2}, x \geq 3

x + 3, - x + 3

Solution steps

y = (x - 3)^{2}

Replace

x

with

y

x = (y - 3)^{2}

Solve for

y, x = (y - 3)^{2}

x + 3, - x + 3

sin (3 x + 1)

y = 2 x + 2

ln (1 - x^{2})

y = \frac{x - 2}{x - 81}

x^{3} - 9

What is the inverse of f(x)=(x-3)^2,x>= 3 ?
The inverse of f(x)=(x-3)^2,x>= 3 is sqrt(x)+3,-sqrt(x)+3