What is the domain of f(x)=(2x+1)/(sqrt(x^2+3x-28)) ?

The domain of f(x)=(2x+1)/(sqrt(x^2+3x-28)) is x 4

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domain of f(x)=(2x+1)/(sqrt(x^2+3x-28))

domain

f (x) = \frac{2 x + 1}{x ^{2} + 3 x - 28}

x < - 7 or x > 4

Interval Notation

(- \infty, - 7) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 7 or x \geq 4

Find undefined (singularity) points:

x = 4, x = - 7

Combine real regions and undefined points for final function domain

x < - 7 or x > 4

y = \frac{1}{x ^{2}}

g (x) = \frac{x ^{2} + 5}{x ^{2} - x - 20}

f (x) = (1.04)^{x}

2 cos (3 x - \frac{π}{2})

f (x) = \frac{7 x + 3}{x + 2}

What is the domain of f(x)=(2x+1)/(sqrt(x^2+3x-28)) ?
The domain of f(x)=(2x+1)/(sqrt(x^2+3x-28)) is x<-7\lor x>4