What is the domain of f(x)= 2/(1/x+3) ?

The domain of f(x)= 2/(1/x+3) is x 0

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domain of f(x)= 2/(1/x+3)

domain

f (x) = \frac{2}{\frac{1}{x} + 3}

x < - \frac{1}{3} or - \frac{1}{3} < x < 0 or x > 0

Interval Notation

(- \infty, - \frac{1}{3}) \cup (- \frac{1}{3}, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{3}, x = 0

The function domain

x < - \frac{1}{3} or - \frac{1}{3} < x < 0 or x > 0

f (x) = 36 - x^{2}

\frac{x + x ( 2 x ^{2} - 5 )}{2 x ^{2} - 5}

f (x) = 5 x^{\frac{1}{3}} + 4

f (x) = \frac{3 x - 9}{- 2 x + 3}

f (x) = 3 x^{0.3}

What is the domain of f(x)= 2/(1/x+3) ?
The domain of f(x)= 2/(1/x+3) is x<-1/3 \lor-1/3 <x<0\lor x>0