What is the domain of f(x)=sqrt(16-x^2)-sqrt(x+2) ?

The domain of f(x)=sqrt(16-x^2)-sqrt(x+2) is -2<= x<= 4

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domain of f(x)=sqrt(16-x^2)-sqrt(x+2)

domain

f (x) = 16 - x^{2} - x + 2

- 2 \leq x \leq 4

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 4

The function domain

- 2 \leq x \leq 4

(5, - 3), (7, - 6)

(\frac{3}{x - 2}) (x - 1)

x + 3 y = - 3

11 x + 1

(0, 4), (0.002224, 20)

What is the domain of f(x)=sqrt(16-x^2)-sqrt(x+2) ?
The domain of f(x)=sqrt(16-x^2)-sqrt(x+2) is -2<= x<= 4