What is the extreme f(x)=3x^3-36x-9 ?

The extreme f(x)=3x^3-36x-9 is Maximum(-2,39),Minimum(2,-57)

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extreme f(x)=3x^3-36x-9

extreme points

f (x) = 3 x^{3} - 36 x - 9

Maximum (- 2, 39), Minimum (2, - 57)

Solution steps

f^{'} (x) = 9 x^{2} - 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

3 x^{3} - 36 x - 9 : 39

Maximum (- 2, 39)

Plug

x = 2

into

3 x^{3} - 36 x - 9 : - 57

Minimum (2, - 57)

Maximum (- 2, 39), Minimum (2, - 57)

f (x) = \frac{5}{x - 6}

- 40 + 8 x = - 10 y

f (x) = \frac{5 x}{x ^{3} + 5 x ^{2} - 6 x}

f (x) = x^{2} - 16, x \leq 0

2 x - 3 y = 6

What is the extreme f(x)=3x^3-36x-9 ?
The extreme f(x)=3x^3-36x-9 is Maximum(-2,39),Minimum(2,-57)