What is the critical x^{2/3}-x^{1/3} ?

The critical x^{2/3}-x^{1/3} is x=0,x= 1/8

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critical x^{2/3}-x^{1/3}

critical points

x^{\frac{2}{3}} - x^{\frac{1}{3}}

x = 0, x = \frac{1}{8}

Solution steps

x^{\frac{2}{3}} - x^{\frac{1}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{8}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{2}{3}} - x^{\frac{1}{3}} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{1}{8}

f (x) = - ∣ x + 1 ∣ - 2

2 x^{2} - 3 x + 5

y = x^{2} - 2 x yy = 2 x

y = 5 x + 2

\frac{( x - 5 )}{( x + 5 )}

What is the critical x^{2/3}-x^{1/3} ?
The critical x^{2/3}-x^{1/3} is x=0,x= 1/8