What is the critical f(x)=(x-3)/(x+7) ?

The critical f(x)=(x-3)/(x+7) is None

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critical f(x)=(x-3)/(x+7)

critical points

f (x) = \frac{x - 3}{x + 7}

None

Solution steps

\frac{x - 3}{x + 7}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 7

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 3}{x + 7} : x < - 7 or x > - 7

\frac{x - 3}{x + 7}

is not defined at

x = - 7

, therefore:

None

x + 4 y = - 4

b^{x}

f (x) = ln (4 - x^{2})

A = 2 X^{1} Q (A, X), (5, 3)

f (x) = 7^{l o g_{7} (x - 1)}