What is the inverse of f(x)=((x-6)^3)/2 ?

The inverse of f(x)=((x-6)^3)/2 is \sqrt[3]{2}\sqrt[3]{x}+6

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inverse of f(x)=((x-6)^3)/2

inverse

f (x) = \frac{( x - 6 ) ^{3}}{2}

Solution steps

y = \frac{( x - 6 ) ^{3}}{2}

Replace

x

with

y

x = \frac{( y - 6 ) ^{3}}{2}

Solve for

y, x = \frac{( y - 6 ) ^{3}}{2}

f (x) = x^{2} + y^{2} = 25

f (x) = \frac{x}{5} - 8

- 2 x^{2} + 5 x - 8

3 lo g_{10} (x - 1)

f (x) = - 4 (\frac{5}{2})^{x + 3} + 1

What is the inverse of f(x)=((x-6)^3)/2 ?
The inverse of f(x)=((x-6)^3)/2 is \sqrt[3]{2}\sqrt[3]{x}+6