What is the inverse of f(x)=x^2+2,x>= 0 ?

The inverse of f(x)=x^2+2,x>= 0 is sqrt(x-2),-sqrt(x-2)

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inverse of f(x)=x^2+2,x>= 0

inverse

f (x) = x^{2} + 2, x \geq 0

x - 2, - x - 2

Solution steps

y = x^{2} + 2

Replace

x

with

y

x = y^{2} + 2

Solve for

y, x = y^{2} + 2

x - 2, - x - 2

4 x - 7 y = - 28

f (x) = 2 x^{2} - 39

f (x) = - (x^{2} + x - 42)

f (x) = 3 x^{3} - 9 x

\frac{20 x + 99}{x ( x + 11 )}

What is the inverse of f(x)=x^2+2,x>= 0 ?
The inverse of f(x)=x^2+2,x>= 0 is sqrt(x-2),-sqrt(x-2)