What is the inverse of g(x)=x^2+8x ?

The inverse of g(x)=x^2+8x is -4+sqrt(x+16),-sqrt(x+16)-4

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inverse of g(x)=x^2+8x

inverse

g (x) = x^{2} + 8 x

- 4 + x + 16, - x + 16 - 4

Solution steps

y = x^{2} + 8 x

Replace

x

with

y

x = y^{2} + 8 y

Solve for

y, x = y^{2} + 8 y

- 4 + x + 16, - x + 16 - 4

\frac{1}{2 x ^{3} - 4 x}

\frac{5 x - 2}{x + 9}

f (x) = x^{5} - x

f (x) = \frac{x ^{2} - x}{x ^{2} - 9 x + 8}

3^{x}

What is the inverse of g(x)=x^2+8x ?
The inverse of g(x)=x^2+8x is -4+sqrt(x+16),-sqrt(x+16)-4