What is the perpendicular y=-3/5 x+11,(4,-8) ?

The perpendicular y=-3/5 x+11,(4,-8) is y= 5/3 x-44/3

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perpendicular y=-3/5 x+11,(4,-8)

perpendicular

y = - \frac{3}{5} x + 11, (4, - 8)

y = \frac{5}{3} x - \frac{44}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{3}{5} x + 11

that passes through

(4, - 8)

Find the slope of

y = - \frac{3}{5} x + 11 : m = - \frac{3}{5}

Compute the slope of the perpendicular line:

m_{p} = \frac{5}{3}

Find the line with slope m=

\frac{5}{3}

and passing through

(4, - 8) : y = \frac{5}{3} x - \frac{44}{3}

y = \frac{5}{3} x - \frac{44}{3}

f (x) = \frac{- x ^{2} + 4}{- 3 x}

f (x) = x^{3} - x^{2} + 3

4.25 cos (6 t) + 5.75

f (x) = \frac{5}{9} (y - 32)

4 x + 5 y = 7, (4, - 3)

What is the perpendicular y=-3/5 x+11,(4,-8) ?
The perpendicular y=-3/5 x+11,(4,-8) is y= 5/3 x-44/3