What is the critical f(x)=(x^2-4)^{2/3} ?

The critical f(x)=(x^2-4)^{2/3} is x=-2,x=0,x=2

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critical f(x)=(x^2-4)^{2/3}

critical points

f (x) = (x^{2} - 4)^{\frac{2}{3}}

x = - 2, x = 0, x = 2

Solution steps

(x^{2} - 4)^{\frac{2}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

(x^{2} - 4)^{\frac{2}{3}} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 2

2 x^{3} - 24 x - 5

f (x) = \frac{x}{4}

f (x) = (x - 3)^{2}

f (x) = 32 x^{5}

f (x) = - \frac{1}{x ^{2}}

What is the critical f(x)=(x^2-4)^{2/3} ?
The critical f(x)=(x^2-4)^{2/3} is x=-2,x=0,x=2