What is the line (0.01,0.2),(0.025,0.8) ?

The line (0.01,0.2),(0.025,0.8) is y=40x-0.2

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line (0.01,0.2),(0.025,0.8)

line

(0.01, 0.2), (0.025, 0.8)

y = 40 x - 0.2

Solution steps

Find the line

y = mx + b

passing through

(0.01, 0.2)

(0.025, 0.8)

Compute the slope

(0.01, 0.2), (0.025, 0.8) : m = 40

Compute the

y

intercept:

b = - 0.2

Construct the line equation

y = mx + b

where

m = 40

and

b = - 0.2

y = 40 x - 0.2

g (x) = \frac{1}{x} - 2

f (x) = cos (x^{2})

\frac{( x ^{3} - x )}{1 + x ^{2}}

f (x) = \frac{4}{t ^{2} - 1}

F (C) = \frac{9}{5} C + 32

What is the line (0.01,0.2),(0.025,0.8) ?
The line (0.01,0.2),(0.025,0.8) is y=40x-0.2