What is the domain of f(x)=sqrt(x^2-6x-7) ?

The domain of f(x)=sqrt(x^2-6x-7) is x = 7

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domain of f(x)=sqrt(x^2-6x-7)

domain

f (x) = x^{2} - 6 x - 7

x \leq - 1 or x \geq 7

Interval Notation

(- \infty, - 1] \cup [7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 7

The function domain

x \leq - 1 or x \geq 7

f (x) = - x - 2

(4, 7), (0, 3)

f (x) = \frac{3 x}{x ^{2} - 16}

f (x) = 5 x + 2

5

What is the domain of f(x)=sqrt(x^2-6x-7) ?
The domain of f(x)=sqrt(x^2-6x-7) is x<=-1\lor x>= 7