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Popular >

extreme f(x)= 1/(x^2+2x+2)

Solution

extreme points

f (x) = \frac{1}{x ^{2} + 2 x + 2}

Solution

Maximum (- 1, 1)

Solution steps

f^{'} (x) = - \frac{2 x + 2}{( x ^{2} + 2 x + 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < \infty

Plug

x = - 1

into

\frac{1}{x ^{2} + 2 x + 2} : 1

Maximum (- 1, 1)

Popular Examples

symmetry 2x^2+4x-1 symmetry

2 x^{2} + 4 x - 1

slope of y=3x-5 slope

y = 3 x - 5

extreme f(x)=(x^2+4)/(8x)extreme points

f (x) = \frac{x ^{2} + 4}{8 x}

midpoint (89,43),(73,-66)midpoint

(89, 43), (73, - 66)

monotone f(x)=x^2+6x+9 monotone intervals

f (x) = x^{2} + 6 x + 9

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 1/(x^2+2x+2) ?
The extreme f(x)= 1/(x^2+2x+2) is Maximum(-1,1)