en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (-2,5),(6,-9)

Solution

midpoint

(- 2, 5), (6, - 9)

Solution

(2, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 2, 5), (x_{2}, y_{2}) = (6, - 9)

= (\frac{6 - 2}{2}, \frac{- 9 + 5}{2})

Refine

= (2, - 2)

Popular Examples

inflection (x^3)/(x^2+5)inflection points

\frac{x ^{3}}{x ^{2} + 5}

domain of (10)/(sqrt(1-x))domain

\frac{10}{1 - x}

inverse of f(x)=x^{11}inverse

f (x) = x^{11}

critical ((3e^x))/(3e^x+7)critical points

\frac{( 3 e ^{x} )}{3 e ^{x} + 7}

inverse of f(x)=log_{4}(x)inverse

f (x) = lo g_{4} (x)

Frequently Asked Questions (FAQ)

What is the midpoint (-2,5),(6,-9) ?
The midpoint (-2,5),(6,-9) is (2,-2)