What is the inverse of f(x)=((3x-5))/((2x+7)) ?

The inverse of f(x)=((3x-5))/((2x+7)) is (-5-7x)/(2x-3)

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inverse of f(x)=((3x-5))/((2x+7))

inverse

f (x) = \frac{( 3 x - 5 )}{( 2 x + 7 )}

\frac{- 5 - 7 x}{2 x - 3}

Solution steps

y = \frac{3 x - 5}{2 x + 7}

Replace

x

with

y

x = \frac{3 y - 5}{2 y + 7}

Solve for

y, x = \frac{3 y - 5}{2 y + 7}

\frac{- 5 - 7 x}{2 x - 3}

f (x) = - 6 x - 7

f (x) = 2.8 + 4.2 x - 1.6 x^{2}

f (x) = \frac{4 x + 9}{3 x - 6}

(\frac{π}{6}, 6), (\frac{π}{4}, 0)

f (x) = \frac{x - 4}{x ^{2} - 6 x + 8}

What is the inverse of f(x)=((3x-5))/((2x+7)) ?
The inverse of f(x)=((3x-5))/((2x+7)) is (-5-7x)/(2x-3)