What is the range of f(x)=(x-2)/((x-2)^2) ?

The range of f(x)=(x-2)/((x-2)^2) is f(x) 0

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range of f(x)=(x-2)/((x-2)^2)

range

f (x) = \frac{x - 2}{( x - 2 ) ^{2}}

f (x) < 0 or f (x) > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x - 2}{( x - 2 ) ^{2}}

Inverse of

\frac{x - 2}{( x - 2 ) ^{2}} : \frac{1}{x} + 2

\frac{1}{x} + 2

Find the domain of each inverse function

Domain of

\frac{1}{x} + 2 : x < 0 or x > 0

Combine the intervals

f (x) < 0 or f (x) > 0

f (x) = \frac{1}{x - 4} + 1

(0, 0), (r, h)

y = ln (x + 3)

3 x + 6 y = 5

4 x + 4 y = 4

What is the range of f(x)=(x-2)/((x-2)^2) ?
The range of f(x)=(x-2)/((x-2)^2) is f(x)<0\lor f(x)>0