What is the line (-2pi,0),(-(3pi)/2 ,-A/2) ?

The line (-2pi,0),(-(3pi)/2 ,-A/2) is y=-A/pi x-2A

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line (-2pi,0),(-(3pi)/2 ,-A/2)

line

(- 2 π, 0), (- \frac{3 π}{2}, - \frac{A}{2})

y = - \frac{A}{π} x - 2 A

Solution steps

Find the line

y = mx + b

passing through

(- 2 π, 0)

(- \frac{3 π}{2}, - \frac{A}{2})

Compute the slope

(- 2 π, 0), (- \frac{3 π}{2}, - \frac{A}{2}) : m = - \frac{A}{π}

Compute the

y

intercept:

b = - 2 A

Construct the line equation

y = mx + b

where

m = - \frac{A}{π}

and

b = - 2 A

y = - \frac{A}{π} x - 2 A

f (x) = x^{2} + 9

f (x) = (4 - x)^{\frac{1}{4}}

f (x) = \frac{x ^{2} + 1}{x - 1}

f (x) = \frac{x ^{2} - 4}{x ^{2}}

m = 2, (1, 4)

What is the line (-2pi,0),(-(3pi)/2 ,-A/2) ?
The line (-2pi,0),(-(3pi)/2 ,-A/2) is y=-A/pi x-2A