What is the inverse of f(x)=(2x^2-16)/(x+2) ?

The inverse of f(x)=(2x^2-16)/(x+2) is (x+sqrt(x^2-8(-16-2x)))/4 ,(x-sqrt(x^2-8(-16-2x)))/4

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inverse of f(x)=(2x^2-16)/(x+2)

inverse

f (x) = \frac{2 x ^{2} - 16}{x + 2}

\frac{x + x ^{2} - 8 ( - 16 - 2 x )}{4}, \frac{x - x ^{2} - 8 ( - 16 - 2 x )}{4}

Solution steps

y = \frac{2 x ^{2} - 16}{x + 2}

Replace

x

with

y

x = \frac{2 y ^{2} - 16}{y + 2}

Solve for

y, x = \frac{2 y ^{2} - 16}{y + 2}

\frac{x + x ^{2} - 8 ( - 16 - 2 x )}{4}, \frac{x - x ^{2} - 8 ( - 16 - 2 x )}{4}

f (x) = ln (x + 1)

f (x) = \frac{( x + 2 )}{x ^{2} + 6 x + 8}

2 x

f (x) = \frac{x}{x - 9}

f (x) = \frac{( 8 x - 7 )}{( 5 x + 8 )}

What is the inverse of f(x)=(2x^2-16)/(x+2) ?
The inverse of f(x)=(2x^2-16)/(x+2) is (x+sqrt(x^2-8(-16-2x)))/4 ,(x-sqrt(x^2-8(-16-2x)))/4