What is the inverse of log_{3}(4^x-4) ?

The inverse of log_{3}(4^x-4) is (ln(3^x+4))/(2ln(2))

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inverse of log_{3}(4^x-4)

inverse

lo g_{3} (4^{x} - 4)

\frac{ln ( 3 ^{x} + 4 )}{2 ln ( 2 )}

Solution steps

y = lo g_{3} (4^{x} - 4)

Replace

x

with

y

x = lo g_{3} (4^{y} - 4)

Solve for

y, x = lo g_{3} (4^{y} - 4)

\frac{ln ( 3 ^{x} + 4 )}{2 ln ( 2 )}

f (x) = (x - 3) x^{2}

f (x) = 1 - 2 x

(- 3, 2), (4, - 5)

f (x) = \frac{5 e ^{x} - 2}{e ^{x} + 8}

f (x) = ln (x^{2} + 2 x - 15)

What is the inverse of log_{3}(4^x-4) ?
The inverse of log_{3}(4^x-4) is (ln(3^x+4))/(2ln(2))