What is the domain of f(x)=(x^2-9)/(x-3) ?

The domain of f(x)=(x^2-9)/(x-3) is x 3

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domain of f(x)=(x^2-9)/(x-3)

domain

f (x) = \frac{x ^{2} - 9}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = x^{2} - 3 x + 2

f (x) = x^{9} + 15 x^{6} + 75 x^{3} + 130

f (y) = 6 x + 8 y = - 10

\frac{3 x}{x ^{2} - 4}

f (x) = \frac{4}{1 + 2 ( 0.5 ) ^{x}}

What is the domain of f(x)=(x^2-9)/(x-3) ?
The domain of f(x)=(x^2-9)/(x-3) is x<3\lor x>3