What is the domain of f(x)=1+(2+x)^{1/2} ?

The domain of f(x)=1+(2+x)^{1/2} is x>=-2

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domain of f(x)=1+(2+x)^{1/2}

domain

f (x) = 1 + (2 + x)^{\frac{1}{2}}

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

(4.9, - 1.3), (- 5.2, - 0.6)

x^{3} - 3 x^{2} + 3 x + 9

5 \cdot 2^{x}

f (x) = (\frac{1}{9})^{x}

f (x) = 2 7^{x}

What is the domain of f(x)=1+(2+x)^{1/2} ?
The domain of f(x)=1+(2+x)^{1/2} is x>=-2