What is the domain of f(x)= 1/(x+7)+3/(x-9) ?

The domain of f(x)= 1/(x+7)+3/(x-9) is x 9

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domain of f(x)= 1/(x+7)+3/(x-9)

domain

f (x) = \frac{1}{x + 7} + \frac{3}{x - 9}

x < - 7 or - 7 < x < 9 or x > 9

Interval Notation

(- \infty, - 7) \cup (- 7, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = - 7, x = 9

The function domain

x < - 7 or - 7 < x < 9 or x > 9

x^{2} - 4 x - 5

15 x^{4} - 90 x^{2}

f (x) = \frac{( 2 x - 3 )}{( x - 2 ) ( x - 3 )}

f (x) = \frac{- 4}{2 x - 1}

(6, 2), (9, 8)

What is the domain of f(x)= 1/(x+7)+3/(x-9) ?
The domain of f(x)= 1/(x+7)+3/(x-9) is x<-7\lor-7<x<9\lor x>9