What is the range of \sqrt[3]{1-2x} ?

The range of \sqrt[3]{1-2x} is -infinity <f(x)<infinity

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range of \sqrt[3]{1-2x}

range

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

Inverse of

- \frac{x ^{3} - 1}{2}

Find the domain of each inverse function

Domain of

- \frac{x ^{3} - 1}{2} : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

f (x) = 6 x - 36

(x + 8)^{8}

y = cos (x - \frac{π}{2})

f (x) = 5 x - 9 = - 8 y - 3

f (x) = \frac{1}{7} x^{2}

What is the range of \sqrt[3]{1-2x} ?
The range of \sqrt[3]{1-2x} is -infinity <f(x)<infinity